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900=100w-w^2
We move all terms to the left:
900-(100w-w^2)=0
We get rid of parentheses
w^2-100w+900=0
a = 1; b = -100; c = +900;
Δ = b2-4ac
Δ = -1002-4·1·900
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-80}{2*1}=\frac{20}{2} =10 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+80}{2*1}=\frac{180}{2} =90 $
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